NajeebKhanOrclApex

 how to Remove success message in oracle apex 20.1 20.2 and any lower versions? step no 1:go to dynamic actions and make one dynamic action on page load like the following figure 01  step no 2: make true action and set action execute javascript code step no 3: Write the following function in setting code setTimeout(function(){  $('#APEX_SUCCESS_MESSAGE').fadeOut('fast'); },3000) and save it it will remove success message when any submit buttons are clicked  Subscribe our channel in youtube :Najeeb Alikel  https://www.youtube.com/results?search_query=najeeb+alikhel

 how to user javascript function to open a model in oracle Apex 20.1 19.1 or any version? First create two regions one for button which should be normal and second  should be model with some data like the following and static id is IRreport         Create one button in the first region button_region and its dynamic actions will be like this        the above js function should be created on page based in function and global variable declaration  like in the following  Note: Remember we IRreport .it is the static id of that model report For Closing the report  1. create another function in global area and write instead of open close         subscribe our channel : Najeeb Alikhel  https://www.youtube.com/results?search_query=najeeb+alikhel

 how to use dynamic action hide and show in oracle apex 20.1 version? step 1: Create two regions one for single item select list  and second for emp report  as the following  the first region should be static content and with one item  p3_select_list and lOV Static  values: show and hide second region is report  interactive report  sql query: select * from employees; dynamic action is on click and true action is: false action: this is a final output    najeebalikhel@gmail.com youtube channel : Najeeb Alikhel subscribe our channel for videos  https://www.youtube.com/results?search_query=najeeb+alikhel